1.6 practice a geometry answers

Lemon

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04-02-2025

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1.6 Practice: Geometry Answers – A Comprehensive Guide

This guide provides answers and explanations for a hypothetical 1.6 practice set in geometry. Since I don't have access to a specific textbook or worksheet labeled "1.6 Practice," I will create a representative set of problems covering common geometry topics found in a typical 1.6 section of a geometry curriculum. This will cover concepts such as angles, lines, and basic shapes. Remember to always check your textbook and teacher's instructions for the correct answers to your specific assignment.

Section 1: Angles

Problem 1: Find the measure of the complement of a 35° angle.

Answer: The complement of an angle is the angle that, when added to the original angle, equals 90°. Therefore, the complement of a 35° angle is 90° - 35° = 55°.

Problem 2: Find the measure of the supplement of a 110° angle.

Answer: The supplement of an angle is the angle that, when added to the original angle, equals 180°. Therefore, the supplement of a 110° angle is 180° - 110° = 70°.

Problem 3: Two angles are vertical angles. If one angle measures 78°, what is the measure of the other angle?

Answer: Vertical angles are the angles opposite each other when two lines intersect. Vertical angles are always congruent (equal in measure). Therefore, the measure of the other angle is also 78°.

Section 2: Lines and Angles

Problem 4: Lines AB and CD intersect at point E. ∠AEB measures 4x + 10 and ∠CED measures 6x - 20. Find the value of x and the measure of ∠AEB.

Answer: ∠AEB and ∠CED are vertical angles, so they are equal. Set up the equation: 4x + 10 = 6x - 20. Solving for x, we get 2x = 30, so x = 15. Substitute x back into the equation for ∠AEB: 4(15) + 10 = 70°. Therefore, ∠AEB = 70°.

Problem 5: Line m is parallel to line n, and line l is a transversal. If ∠1 measures 115°, find the measure of ∠5.

Answer: Assuming ∠1 and ∠5 are corresponding angles (they are in the same relative position on the transversal and parallel lines), then they are congruent. Therefore, ∠5 also measures 115°.

Section 3: Basic Shapes

Problem 6: Find the perimeter of a rectangle with length 8cm and width 5cm.

Answer: The perimeter of a rectangle is given by the formula P = 2(length + width). Therefore, P = 2(8cm + 5cm) = 2(13cm) = 26cm.

Problem 7: Find the area of a triangle with a base of 10 inches and a height of 6 inches.

Answer: The area of a triangle is given by the formula A = (1/2) * base * height. Therefore, A = (1/2) * 10 inches * 6 inches = 30 square inches.

Important Note: This is a sample practice set. The actual problems and concepts covered in your 1.6 practice might differ. Always refer to your textbook or class materials for the most accurate information and solutions. If you are still struggling with any specific problem, try re-reading the relevant section in your textbook or seeking help from your teacher or a tutor. Remember to show your work for each problem to demonstrate your understanding of the concepts.